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This blog is intended to share my knowledge about software architecture, system design, tools, and techniques for producing high-quality products.

LeetCode - Blind 75 - Decode Ways

The Problem You have intercepted a secret message encoded as a string of numbers. The message is decoded via the following mapping: "1" → 'A' "2" → 'B' … "25" → 'Y' "26" → 'Z' However, while decoding the message, you realize that there are many different ways to decode it because some codes are contained within others (e.g., "2" and "5" vs. "25"). For example, "11106" can be decoded into: ...

March 23, 2025 Â· 5 min Â· Dmytro Chumakov

LeetCode - Blind 75 - Palindromic Substrings

The Problem Given a string s, return the number of palindromic substrings in it. A string is a palindrome when it reads the same backward as forward. A substring is a contiguous sequence of characters within the string. Examples Input: s = "abc" Output: 3 Explanation: Three palindromic strings: "a", "b", "c". Input: s = "aaa" Output: 6 Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa". Constraints 1 <= s.length <= 1000 s consists of lowercase English letters. Brute Force Solution func countSubstrings(_ s: String) -> Int { let n = s.count let sArray = Array(s) var res = 0 for i in 0 ..< n { for j in i ..< n { var l = i var r = j while l < r && sArray[l] == sArray[r] { l += 1 r -= 1 } res += (l >= r) ? 1 : 0 } } return res } Explanation We can solve this problem by understanding how a brute-force approach works and then optimizing it. ...

March 21, 2025 Â· 4 min Â· Dmytro Chumakov

LeetCode - Blind 75 - Longest Palindromic Substring

The Problem Given a string s, return the longest palindromic substring in s. A string is palindromic if it reads the same forward and backward. Examples Input: s = "babad" Output: "bab" Explanation: "aba" is also a valid answer. Input: s = "cbbd" Output: "bb" Constraints 1 <= s.length <= 1000 s consists of only digits and English letters. Brute Force Solution func longestPalindrome(_ s: String) -> String { let sArray = Array(s) var res = "" var resLen = 0 let n = s.count for i in 0 ..< n { for j in i ..< n { var l = i var r = j while l < r && sArray[l] == sArray[r] { l += 1 r -= 1 } if l >= r && resLen < (j - i + 1) { res = String(sArray[i ..< j + 1]) resLen = j - i + 1 } } } return res } Explanation In the first example, we are given the input "babad". Let’s visualize it and try to find the longest palindromic substring. ...

March 19, 2025 Â· 4 min Â· Dmytro Chumakov

LeetCode - Blind 75 - House Robber II

The problem You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses in this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent houses have a security system connected, and it will automatically contact the police if two adjacent houses are broken into on the same night. ...

March 17, 2025 Â· 5 min Â· Dmytro Chumakov

LeetCode - Blind 75 - House Robber

The Problem You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. The only constraint stopping you from robbing each of them is that adjacent houses have security systems connected, and they will automatically contact the police if two adjacent houses are broken into on the same night. Given an integer array nums representing the amount of money in each house, return the maximum amount of money you can rob tonight without alerting the police. ...

March 14, 2025 Â· 5 min Â· Dmytro Chumakov